Resistance Value?

[Karl W4KRL]

One ohm cannot be correct. If you eliminate all resistors except the four
that connect the two measurement points you end up with two one ohm
resistors in series that are in parallel with two other one ohm resistors in
series hence one ohm between the measurement terminals. Since the rest of
the infinite network is in parallel with these resistors the value must be
less than one ohm.

Karl W4KRL

-----Original Message-----
From: Richard O'Neill [mailto:richardoneill at earthlink.net] 
Sent: Thursday, October 25, 2012 7:04 PM
To: tacos at amrad.org
Subject: Re: Resistance Value?

  Correct! You win the Grand Prize, a one ohm resistor. :-) Would you care
to inform us how you arrived at the answer?

Richard


On 10/25/2012 6:34 PM, Phil wrote:
> One ohm.
>
> Phil M1GWZ
>
>
> On 25 Oct 2012, at 20:32, Karl W4KRL wrote:
>
>> My solution is based on observing that an infinite number of parallel 
>> resistors approaches zero resistance. Each row and column of 
>> resistors can be reduced to a short circuit connected to the "center" 
>> elements through two series resistors.
>>
>> Karl W4KRL
>>
>> -----Original Message-----
>> From: Richard O'Neill [mailto:richardoneill at earthlink.net]
>> Sent: Thursday, October 25, 2012 2:14 PM
>> To: W4KRL at arrl.net
>> Cc: Karl W4KRL; 'Tacos AMRAD'
>> Subject: Re: Resistance Value?
>>
>>
>>   Awaiting your drawing. :-) The proof of Fermat's last theorem 
>> required
>> 358 years but this problem isn't that difficult to solve.
>> In fact, it's intuitively obvious and a good exercise for EE's. :-D
>>
>> Richard
>>
>> On 10/25/2012 12:24 AM, Karl W4KRL wrote:
>>> My non-mathematical approach yields 1/2 Ohm. Am I correct? If so I 
>>> will draw the approach tomorrow.
>>>
>>> Karl W4KRL
>>>
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